Asked by yash

A pistol of mass 2kg fires a bullet of mass 50g. The bullet strikes a block of mass 0.5kg. If the block with bullet embedded in it moves with a velocity of 4m/s the recoil velocity of the gun will be..??
Answered by Damon
find bullet momentum from conservation of momentum
.05 v = .55 * 4 = 2.2

then
2 V + 2.2 = 0
V = -2.2/2

Answered by dhruv rawat
correct -1.10
Answered by arnav
@damon can you please explain it...
Answered by vipin
0.5 and 0.55 are not given in the Q.
just memorizing don't work in physics when u cant explain the answer
Answered by Tanishq Hitesh
mass of bullet and block = 1.1/2
momentum = 1.1/2¡Á4 = 2.2kg.m/s
2.2= 2¡Á velocity of bullet
velocity=-1.10m/s
Answered by chirag
-1.110 m/s
Answered by aaditi
plzzz explain ...... i m not geeting
Answered by aaditi
plzzz explain ...... i m not geeting

Answered by Sneha
what is the ans
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