a pile of bricks has 97 bricks in the first row, 91 bricks in the second row, 85 bricks in the third row, and so on until there is only one brick in the top row how many bricks are in the 15th row

Answer 1

well I guess we have an arithmetic sequence where a = 97 and d = -6
https://www.mathsisfun.com/algebra/sequences-sums-arithmetic.html
d + d(n-1)
97 - 6(14)

Answer 2

This is just an AP, with
A1 = 97
d = -6
and you want to find A15 = A1 + 14d
so plug in your numbers

Answer 3

97x 15=14x-6

Answer 4

Asan yung sagot

Answer 5

a pile of bricks has 97 bricks in the first row, 91 bricks in the second row, 85 bricks in the third row, and so on until there is only one brick in the top row how many bricks are in the 10th row