volume of wood = V
density of wood = rhowood
density of liquid = .8 * rho water = 800 kg/m^3
density of water = 1000 kg/m^3
in liquid
rhowood * g * V = (5/6) * 800 *g * V
so
rhowood = 5 *800 / 6 = 2000/3 = 2/3 * density of water
so 1/3 of the wood is out of water
A piece of wood of uniform cylindrical cross section floats upright in a liquid of relative density 0.80 with 1/6 of its height above the liquid. If placed in water, what is the fraction of its height above the water level?
1 answer