[mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
Plug in all the numbers given and solve for specific heat metal.
Post your work if you get stuck.
A piece of metal of mass 15 g at 119 ◦C is
placed in a calorimeter containing 48.8 g of
water at 23◦C. The final temperature of the
mixture is 58.9◦C. What is the specific heat
capacity of the metal? Assume that there is
no energy lost to the surroundings.
1 answer