specific gravity = 49 / (49 - 39.2)
(x * 19.3) + [(1 - x) * 2.5] = specific gravity
x is the fraction of the alloy that is gold
A piece of gold-aluminium alloy weighs 49N when suspended from a spring balance and submerged in water it weighs 39.2N what is the weight of Gold in the alloy if the specific gravity of gold is 19.3 and aluminium is 2.5?
2 answers
19.3 + 2.5 = 21.8.
19.3/21.8*49 = 43.4 N. of gold.
49-43.4 = 5.6 N. of of aluminum.
19.3/21.8*49 = 43.4 N. of gold.
49-43.4 = 5.6 N. of of aluminum.