A physics student stands on the edge of a cliff 2x meters. He throws his physics homework straight up in the air. Derive an expression to calculate the time taken by the homework to come back to the student.
2 answers
Vf=Vi+at
Nope, time works here:
hf=hi+vi*t-1/2 *(9.8)t^2
but hf=hi
t(vi-4.9t)=0
t=vi/4.9
hf=hi+vi*t-1/2 *(9.8)t^2
but hf=hi
t(vi-4.9t)=0
t=vi/4.9
1 answer