A physics student stands on top of a hill that has an elevation of 56 meters. He throws a rock and it goes up into the air and then falls past him and lands on the ground below. The path of the rock can be modeled by the equation -

Question

y=-0.04x^2+1.3x+56 where x is the horizontal distance in meters from the starting point on the top of the hill and y is the height in meters of the rock above the ground.
How far horizontally from the starting point will the rock land?

a- 56.0m
b- 24.54m
c- 57.,04m
d- 57.26m

Grandpa asking for help again.

Answer 1

0 = -0.04x^2+1.3x+56
or
0 = 0.04x^2 - 1.3x - 56
solve quadratic

Answer 2

thank you