A photon interacts with a ground state electron in a hydrogen atom and is absorbed. The electron is ejected from the atom and exhibits a de Broglie wavelength of 5.908×10−10 m. Determine the frequency (in hz) of the interacting photon.

Answer 1

E = P^2/2Me + E(first ionization)

P= h / BroglieWavelength

E(first ionization)=21.7*10^-19

Me= 9.1*10^-31

h= 6.626*10^-34

frecuency(hz)= E / h

Answer 2

Chemgam, can you please clarify what is (P^2)? do you mean (Momentum) X (Momentum)

I made it like this, but it gave me wrong answer

Answer 3

P = h/ BroglieWavelength

Like he says. It is correct