Asked by kaken

A photon interacts with a ground state electron in a hydrogen atom and is absorbed. The electron is ejected from the atom and exhibits a de Broglie wavelength of 1.828×10−10 m. Determine the frequency (in hz) of the interacting photon.
Answered by chacho
4.329E15
Answered by babalovic
wrong answer
Answered by schoolgirl
Would you please give the formula?
Answered by martin
chacho,could you please explain the answer when de broglie wavelength 0.468*10^-10m.
Answered by T
A photon interacts with a ground state electron in a hydrogen atom and is absorbed. The electron is ejected from the atom and exhibits a de Broglie wavelength of 0.468×10−10 m. Determine the frequency (in hz) of the interacting photon.
Answered by qpt
How do you use the above data and insert into the formula?
Answered by helper
could you explain me this one
A photon interacts with a ground state electron in a hydrogen atom and is absorbed...
And I will explain you the formula
Answered by ani
4.329E15 this answer is not right
Answered by helpmit
7.157215*10^15
Answered by Anonymous
chacho's answer is right if you have in your question de Broglie wavelength of 5.908×10−10 m :-)
Answered by ani
this answer also not righ
Answered by schoolgirl
Formula please...
Answered by Anonymous
2.3E19
Answered by Atef (Egypt)
please give us the formula
Answered by qwerty
E = P^2/2Me + E(first ionization)

P= h / BroglieWavelength

E(first ionization)=21.7*10^-19

Me= 9.1*10^-31

h= 6.626*10^-34

frecuency(hz)= E / h
Answered by kaken
I have one question about the formula, is it E = P^2/(2Me + E)(first ionization) or E = P^2/(2Me + E(first ionization) ) ??
Answered by kaken
sorry i wrote the same formula; my questios was if the formula is:

1- E = (P^2/2Me )+ E(first ionization)
or
2- E = P^2/(2Me + E)(first ionization)

sorry for the previous post
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