a pet truck is moving at 25m/s north, a dog inside moves at 1.75 m/s at angle 35 degrees east of north. What is the velocity of the dog relative to the road?

Answer 1

let s be the speed of the dog

s^2 = 25^2 + 1.75^2 - 2(25)(1.75)cos 145°
s = 26.45m/s

Let θ be the direction of travel

sinθ/1.75 = sin145°/26.45
θ = 2.17°

So, the dog's velocity is 26.45 m/s at N2.17°E

Answer 2

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Answer 3

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