A person with the weight of 691 N stands on a bathroom scale in a motionless elevator. The elevator begins to move and the scale momentarily changes to 499 N. (a) Draw a force diagram of the situation. (b) Create a qualitative vertical equation for this situation. (c) Calculate the magnitude and direction of the elevator’s acceleration.

Answer 1

m = 691/9.8

(c) F = ma

Answer 2

R=net force, And net force =mg-ma,m(g-a). R=499,m=691/9.8=70.51kg 499=70.51(9.8-a),find a,and a is directed upward