a person walks first a constant speed of 5.00m/s along a straight line from point A to point B and then back along the line from point B to A at a constant speed of 3.00m/s. (a) what is her average speed over the entire trip? (b) what is her average velocity over the entire trip?
3 answers
4.00m/s
Average speed= vi+vf/2
Average speed= (5m/s +3m/s)/2
Average speed= 4 m/s
Average speed= (5m/s +3m/s)/2
Average speed= 4 m/s
I don't what is the answer because there is no time given at the question