A person walks first at a constant speed of 4.90 m/s along a straight line from point A to point B and then back along the line from B to A at a constant speed of 2.70 m/s.

Question

(a) What is her average speed over the entire trip?

Answer 1

It is not the average of 4.9 and 2.7, because she spends more time walking at the slower speed.

Let the total distance between A and B be D

t1 = D/4.9 t2 = D/2.7

Average speed = 2D/*t1 + t2)
= 2D/[(D/4.9) + (D/2.7)]
= 2/[(1/4.9) + 1/(2.7)] = 3.38 m/s

Answer 2

Ur great but the solution is like .....