a, ay=-9.8m/s^2
b. h=1/2 9.8 t^2 solve for t
c. distance=10*t
d. vx=10, vy=-9.8t
e. v= sqrt(100+vy^2)
A person runs off a cliff. The person runs with a speed of 10 m/s and is moving to the right as he leaves the cliff. The cliff is 13 meters above a pool of water. a) Determine the acceleration of the person after leaving the cliff (x and y components). b) Determine the time it takes the person to hit the water. c) Determine the horizontal displacement of the person from leaving the cliff to hitting the water. d) Determine the velocity (x and y components) of the person just before impact. e) Determine the velocity (magnitude and direction) of the person just before impact.
2 answers
e) the impact angle (Θ) with respect to the pool surface
... tan(Θ) = vy / vx
... tan(Θ) = vy / vx
1 answer