A person is standing on a level floor. His head, upper torso, arms, and hands together weigh 470 N and have a center of gravity that is 1.13 m above the floor. His upper legs weigh 108 N and have a center of gravity that is 0.755 m above the floor. Finally, his lower legs and feet together weigh 87.1 N and have a center of gravity that is 0.250 m above the floor. Relative to the floor, find the location of the center of gravity for the entire body.
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The figure shows a person whose weight is W = 500 N doing push-ups. Find the normal force exerted by the floor on (a) each hand and (b) each foot, assuming that the person holds this position.
(470*1.13 + 108*0.755 + 87.1*0.250)/(470+108+87.1) = 0.954
1 answer