A person holds a ladder horizontally at its center. Treating the ladder as a uniform rod of length 2.65 m and mass 6.84 kg, find the torque the person must exert on the ladder to give it an angular acceleration of 0.301 rad/s2

Question

A person holds a ladder horizontally at its center. Treating the ladder as a uniform rod of length 2.65 m and mass 6.84 kg, find the torque the person must exert on the ladder to give it an angular acceleration of 0.301 rad/s2 
We tried T = mr^2(alpha), but that was wrong. We also tried using the length of the whole ladder instead of the radius, and again, incorrect

Well, you missed the moment of inertia for a thin rod be a factor of 12.

http://www.ac.wwu.edu/~vawter/PhysicsNet/Topics/RotationalKinematics/MomentInertia.html

Thanks man!