vertical = 480+840 = 1320
horizontal force equal and opposite to force at top exerted by wall, F
moments about base of ladder
F*16*sin61 = 480*8*cos61 +840*4.2*cos61
13.99 F = 1862+1710
F = 255 = hor. force on ladder base toward wall
A 16.0 m uniform ladder weighing 480 N rests against a frictionless wall. The ladder makes a 61.0° angle with the horizontal.
(a) Find the horizontal and vertical forces the ground exerts on the base of the ladder when an 840 N firefighter is 4.20 m from the bottom.
i got 271 for this but it says that is wrong due to my rounding in between but i didn't do any intermediate rounding at all, can you double check this again
1 answer
1 answer