The heat capacity 0f 4.18 J/g.ºC is equivalent to 1.00 cal/g.ºC or 1.00kcal/kg.ºC
180kcal = (1.00kcal/kg.ºC)(m)(10.0ºC)
Solve for m
A person falls in water at 0 C. After 30 min in the water, he/she suffers from hypothermia, as their body temp drops to 30 C. Since we are water.... we assume the heat capacity is 4.18 J/g/C. 180 Kcal of energy is required to raise the persons temp to 40 C. I need to find the mass.
You use Q=mc dT but I'm confused about temperature?
I also know that 180 kcal is 753 120 J.
What do we use for dT.. is it 40-30?
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sweet thanks GK!
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