A person exerts a horizontal force of 36 N on the end of a door 97cm wide. What is the magnitude of the torque if the force is exerted perpendicular to the door and What is the magnitude of the torque if the force is exerted at a 70.0 angle to the face of the door?

Question

A person exerts a horizontal force of 36 N  on the end of a door 97cm  wide. What is the magnitude of the torque if the force is exerted perpendicular to the door and What is the magnitude of the torque if the force is exerted at a 70.0 angle to the face of the door?

Thank you

bobpursley · Answer

torque=36N*.97m torque=36N*.97m*cos20