a. torque=28(.84)*sin90 Nm
b. torque=28(.84)*sin45 Nm
c. Torque=28*.84*sin0
so it is the product of force times length* sine of angle between force and door.
A person exerts a force of 28 N on the end of a door 84 cm wide. What is the magnitude of the
torque if the force is exerted
a. perpendicular to the door?
b. at a 45 degree angle to the face of the door?
c. parallel to the door?
1 answer
1 answer