t=2pi*sqrt(L/g)
t=1.25=2pi*sqrt(L/9.8m/s)
Solve for L
9.8m/s^2*(1.25/2pi)^2=L
L=0.388m
I want to increase the period by 0.200 seconds. How long should I increase the length of the pendulum? The new period will be 1.45 seconds. Use the above equation and solve for L:
t=1.45=2pi*sqrt(L/9.8m/s)
9.8m/s^2*(1.45/2pi)^2=L
L=0.522m
0.522m-0.388m=0.134m=13.4cm
a pendulum is swinging back and forth once every 1.25 second, how much longer should the pendulum be to increase its period by 0.200 second
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