multiply the period by sqrt 6. Figure out why this works.
b. if the clock is slower by a factor of sqrt6, then it should be 2hr/sqrt6 hrs. Think about that.
A pendulum clock is accurate on earth, where the period of its pendulum is 1.00 s.
(a) Find its period on the moon, where gravitational acceleration is 1.6 m/s2.
(b) During a 2 h interval, what would be the elapsed time shown on the clock?
CAN YOU PLEASE PROVIDE AN ANSWER WITH WORK . THANK YOU
1 answer
1 answer