1/2 m v^2 = m g h
h = v^2 / (2 g)
A pendulum bob has its maximum speed as 5m/s at lowest position o. Calculate the height of the Bob above o,where its velocity is zero.
2 answers
Vi=5.0m/s upwarrd
vf=0.0m/s
a=-9.8m/s/s
d=?
Vf2=Vi2+2ad
d=(Vf2-Vi2)÷2a
=25÷(2x9.8)=1.27m
vf=0.0m/s
a=-9.8m/s/s
d=?
Vf2=Vi2+2ad
d=(Vf2-Vi2)÷2a
=25÷(2x9.8)=1.27m