A pellet gun is fired straight downward from the edge of a cliff that is 13.4 m above the ground. The pellet strikes the ground with a speed of 26.1 m/s. How far above the cliff edge would the pellet have gone had the gun been fired straight upward?

Answer 1

v = v0 - 9.8t
v0 = -26.1-9.8t

h = 13.4 + v0*t - 4.9t^2
= 13.4 + (-26.1-9.8t)t - 4.9t^2
h=0 when t=0.416

v0 = -26.1-9.8*0.416= -30.17

So, if v0 = +30.17,

h = 13.4 + 30.17t - 4.9t^2
max height at t = 30.17/9.8 = 3.078
h(3.078) = 59.8m

Answer 2

Note that that is not the answer to the question ...