A pellet gun is fired straight downward from the edge of a cliff that is 27.1 m above the ground. The pellet strikes the ground with a speed of 25.9 m/s. How far above the cliff edge would the pellet have gone had the gun been fired straight upward?

Answer 1

vf^2=vi^2+2gd where g=-9.8, d=-27.1

solve for vi.

Now it it had been straight up,
0=Vi^2+2gh solve for h. g=-9.8