Damon C

distance = speed * time

c = 200 + 5 x

600 = .06 n (2000) n = 5

I tried to answer but Jiskha will not allow me to post my reply. In general calculate f(1) = 2 f(1.5) = 2.1 something that is exact to the accuracy of your calculator then calculate f(x+dx) = f(x)+ dx (df/dx) where df/dx = .5/(3+x)^.5 which is (.5 / 2).5...

Help someone, I can no longer reply to questions as me.

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vf^2=vi^2+2gd where g=-9.8, d=-27.1 solve for vi. Now it it had been straight up, 0=Vi^2+2gh solve for h. g=-9.8

h=1/2 g t^2 +Vi*t g=-9.8, h=0 solve for g