A particle's constant acceleration is south at 2.1 m/s2. At t = 0, its velocity is 45.2 m/s east. What is its velocity at t = 7.7 s? What's the magnitude and direction?

Answer 1

Vf=Vi+at
Vf=45.2E+ 2.1*7.7 S

Answer 2

I got 61.37 but I'm getting it wrong