A particle travels horizontally between two parallel walls separated by 18.4 m. It moves toward the opposing wall at a constant rate of 9.4 m/s. Also, it has an acceleration in the direction parallel to the walls of 5.8 m/s^2

Question

What will be its speed when it hits the
opposing wall?
Answer in units of m/s

Answer 1

It will take the particle t = 18.4/9.4 = 1.957 s to go from wall to wall. In doing so, it will acquire a velocity component parallel to the wall equal to
Vy = 5.8*t = 11.35 m/s

Compute the vector sum of 11.35 m/s and 9.4 m/s at right angles