A particle starts at the origin at t=0 with an intial velocity of 5.0m/s along the positive x axis. If the acceleration is (-3.0,4.5) m/s^2, determine the velocity and position of the particle at the moment it reaches its maximum x coordinate. You can't use a calculator.

1 answer

max distance is when at= -initial velocity
t=initial velocity/a in the x direction=
t=5/3 seconds

at that point, the only velocity is j component in the y direction,or 4.5*5/3 j

v=9/5*5/3=3m/s

position:
x componant=5*5/3-1/2 3* 25/9
y component=1/2( 9/5 *25/9