F = k |Q1 Q2| / d^2 = 8.99*10^9 * 80*10^-6* 24*10^-6 / 0.81^2
= 26,308 * 10^-3 = 26.308 N
a = F/m = 26.3/ 0.082
A particle of mass 82 g and charge 80 µC is
released from rest when it is 81 cm from a
second particle of charge −24 µC.
Determine the magnitude of the initial acceleration of the 82 g particle.
Answer in units of m/s
2
3 answers
82/1000 = 0.082
A particle (m = 50 g. q = 5.0 µC) is released from rest when it is 50 cm from a second particle (Q = -20 µC). Determine the magnitude of the initial acceleration of the 50-g particle.
0 answers