A particle moving at a velocity of 8 m/s in the positive x direction is given an acceleration of 7.4 m/s2 in the positive y direction for 1.7 s.

Question

A particle moving at a velocity of 8 m/s in the positive x direction is given an acceleration of 7.4 m/s2 in the positive y direction for 1.7 s.
What is the final speed of the particle? Answer in units of m/s

Steve · Accepted Answer

Vy = 7.4*1.7 = 12.58 m/s So, the final speed is √(8^2+12.58^2) = 14.91 m/s