A particle moving at a velocity of 4.8 m/s in the positive x direction is given an acceleration of 3.4 m/s2 in the positive y direction for
4.4 s. What is the final speed of the particle? Answer in units of m/s.
1 answer
V = Vo + a*t(i) = 4.8 + 3.4i*4.4 = 4.8 + 14.96i = sqrt(4.8^2 + 14.960^2) = 15.71 m/s.
3 answers