Ask a New Question

A particle moving along x-axis has velocity v(t) = sin(4t) at time t. If the particle is at x=4 when t=0, determine the position of the particle when t=pi/2.

2 answers

v(t) = ds/dt, so
s(t) = -1/4 cos(4t) + C
s(0) = -1/4 + C = 4, so C = 17/4
s(π/2) = -1/4 cos(π/2) + 17/4 = 17/4

ayt

Ask a New Question or answer this question.

Similar Questions

The acceleration of a particle at a time t moving along the x-axis is give by: a(t) = 4e^(2t). At the instant when t=0, the
1. 2 answers
The velocity graph of a particle moving along the x-axis is shown. The particle has zero velocity at t=0.00s and reaches a
1. 3 answers
The position of a particle moving along the x-axis at time t > 0 seconds is given by the function x(t) = e ^ t - 2t feet.a) Find
1. 1 answer
The velocity of a particle on the x-axis is given by the differential equation dx/dt= t^2/ 2 and the particle is at x = 4 when t
1. 4 answers

more similar questions