A particle moves along a line so that at time t, where 0<=t<=pi, its position is given by

Question

s(t)= -4cost-((t^2)/2)+10 What is the velocity of the particle when its acceleration is zero?
a. 8.13
b. 1.32
c. 0.74
d. -5.19
e. 2.55
I know that c and b are incorrect
Please help me

Answer 1

Your function is odd, I read it as

Cosine ( t-((t^2/2) ) + 10

check that

Take the derivative, that is velocity
Take the derivative again, and set to zero, solve for t. Put that t into velocity .

Answer 2

Solve for v(t)
V(t) =4sin(t)-t
Solve for a(t)
a(t)=4cos(t)-1
Find when a(t)=0
t=1.32
Plug t into v(t)
ANSWER=2.55

Answer 3

T'is actually 3.969. Thank me later

Answer 4

3.969

Answer 5

it is 2.55