Asked by Pammy

A particle moves in a straight line under a force such that its displacement
s(t), in metres, at time t seconds, is given by s(t) = t3 − 5t2 + 3t +15
(i) Find the expression for the velocity of the particle.
(ii) Find the time at which the particle is at rest.
(iii) Find the acceleration at time t = 5.
Answered by Steve
(i) v(t) = ds/dt
(ii) set v=0 and solve for t
(iii) a(t) = dv/dt; find a(5)
Answered by Anonymous
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