Question
A particle moves in a straight line with velocity given by v(t) =sin t metres per second. Find the total distance travelled by the particle in the first 4 seconds of motion
Answers
integratiing we get
s(t) = -cost + c , where s(t) is distance and c is a constant
s(0( = -cos0 + c = -1+c
s(4) = -cos 4 + c
distance covered = -cos 4 + c - (-1+ c)
= -cos 4 + 1
= appr. 1.6536
make sure your calculator is set to RAD (radians)
s(t) = -cost + c , where s(t) is distance and c is a constant
s(0( = -cos0 + c = -1+c
s(4) = -cos 4 + c
distance covered = -cos 4 + c - (-1+ c)
= -cos 4 + 1
= appr. 1.6536
make sure your calculator is set to RAD (radians)
Related Questions
A particle moves on a vertical line. Its position, s, in metres at t seconds is given by s(t) = t^3...
A particle moves in a straight line under a force such that its displacement
s(t), in metres, at ti...
A particle moves in a straight line with an acceleration a ms^-2 at time 't' seconds where a = - 1/t...
A particle travelling along a straight line starts with a
velociry ofu metres per second and its sp...