A particle is subject to a time-dependent force: F(t)=5t√. If the particle's mass is 7 kg, what will its velocity be at t=6.7 seconds, assuming its initial velocity at t=0 is equal to 0.

Answer 1

That's F(t)=5sqrt(t)

Answer 2

F(t) = 5√t
F=ma, so
a(t) = 5/7 √t
v(t) = 5/7 * (2/3) t^(3/2) + c
v(0) = 0, so c=0 and

v(t) = 10/21 t^(3/2)
so,
v(6.7) = 10/21 * 6.7^(3/2) = 8.26 m/s

Answer 3

Thanks Steve