The resultant vector is
-1.6i +2.9j
and its magnitude is
sqrt[1.6^2 + 2.9^2]= 3.31 N
A particle is acted upon two forces given by the vector equations,
F1=1.5i-0.7j and
F2=-3.1i+3.6j,
with values measured in Newtons(N). Calculate the resultant force, in N, acting on the particle, giving your answer to 3 dec places.
2 answers
-2.3i+4.5j