A particle hangs from a spring and oscillates with a period of 0.2 s.If the mass-spring system remained at rest,

Question

by how much would the mass stretch it from
its normal equilibrium position? The acceleration of gravity is 9.8 m/s^2

Answer 1

((.2)^2)/(4(pi^2))=.0010132118
.0010132118x9.8
0.00992948m

Answer 2

IDK