To find the difference in height between the two measurements, we need to subtract the lower height from the higher height.
- Initial height of the parasail: \( \frac{12}{10} \) of a kilometer (which can be simplified to \( \frac{6}{5} \) kilometers).
- Height after 10 minutes: \( \frac{1}{50} \) of a kilometer.
Now, we need to convert the heights to a common denominator before subtracting.
The least common denominator (LCD) of \( \frac{6}{5} \) and \( \frac{1}{50} \) is 50.
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Convert \( \frac{6}{5} \) to have a denominator of 50: \[ \frac{6}{5} = \frac{6 \times 10}{5 \times 10} = \frac{60}{50} \]
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Now we can subtract \( \frac{1}{50} \) from \( \frac{60}{50} \): \[ \frac{60}{50} - \frac{1}{50} = \frac{60 - 1}{50} = \frac{59}{50} \]
So, the difference in height is \( \frac{59}{50} \) kilometers.
However, this seems to be incorrect in relation to the choices provided. Let's check again the provided heights before concluding based on the options given:
- Convert the heights to decimals for easier understanding:
- \( \frac{12}{10} = 1.2 \) kilometers
- \( \frac{1}{50} = 0.02 \) kilometers
Thus, the height difference becomes: \[ 1.2 - 0.02 = 1.18 \]
Now converting \( 1.18 \) kilometers to a fraction:
- \( 1.18 = \frac{118}{100} = \frac{59}{50} \) kilometers.
This finalizes that:
- The correct answer should represent a simplification oversight.
Now let's revert to options given: To check against the results, none seem relatable. Based on fractions:
- The closest difference related might mean a relook into whether I missed contextual height options.
However, continuing, we can finalize: If concluding on provided options simply versus decimal: None fit awful.
For further clear examination please check which states offer simplified fractions available matching closely drawn.
**Final answer on remains: None matched obvious premises unless clearer direction met. **
If there was specific focus or direct verbiage from host lines given prompt. Please share, I'll correct resultant insights more targeted.