A pair of glasses are dropped from the top of a 32.0 m high stadium. A pen is dropped from the same position 2.00 s later. How long does it take for the glasses to hit the ground? How high above the ground is the pen when the glasses hit the ground? (Disregard air resistance)

Answer 1

Find the time of fall by using:
y = (1/2)gt^2
(y is given and g = 9.8m/s^2, Solve for t)

When the glasses hit the ground, the pen has been falling for (t-2.00s). The height above the ground of the glasses is:
32.0m - (1/2)g(t-2)^2

Answer 2

Correction to the previous answer:
"The height above the ground of the glasses is:
32.0m - (1/2)g(t-2)^2" should read:
The height above the ground of the pen is:
32.0m - (1/2)g(t-2)^2

Answer 3

2 m

Answer 4

25.6

Answer 5

1.5 m

Answer 6

30.51m

Answer 7

30.5