A one-liter container completely filled with mercury has a mass of 13.6 kg and weighs 133.3 N. What is the buoyant force on the container if the container is placed in water?
3 answers
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9.86N
Given:
Volume of container = 1 L = 1000 cm3
= 1 x 103
cm3
since 1 m = 100 cm
then 1 m3
= 1,000,000 cm3
= 1 x 106
cm3
thus 1 L = 1 x 10-3 m3
density of water = 1 x 103
kg/m3
Solution:
Volume of container = volume of water displaced = 1 x 10-6 m3
Weight of water displaced (Ww) = volume of water displaced (Vw) x density of water (ρw)
Ww = Vwρw
= 1 x 10-3 m3
x 1 x 103
kg/m3
= 1 kg
but 1 kg = 9.8 N
therefore Ww = 9.8 N
Volume of container = 1 L = 1000 cm3
= 1 x 103
cm3
since 1 m = 100 cm
then 1 m3
= 1,000,000 cm3
= 1 x 106
cm3
thus 1 L = 1 x 10-3 m3
density of water = 1 x 103
kg/m3
Solution:
Volume of container = volume of water displaced = 1 x 10-6 m3
Weight of water displaced (Ww) = volume of water displaced (Vw) x density of water (ρw)
Ww = Vwρw
= 1 x 10-3 m3
x 1 x 103
kg/m3
= 1 kg
but 1 kg = 9.8 N
therefore Ww = 9.8 N
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