A object starts at a position that is 14.0 m [south] of the origin. If the object then moves at a velocity of 2.80 m/s [north] for 9.10 seconds, what is the final position?

Answer 1

To find the final position of the object, we need to calculate the displacement during the 9.10 seconds of motion.

The initial position is 14.0 m south of the origin, so the initial position is -14.0 m. Since the object moves north, we can consider this as a positive displacement.

The velocity of the object is 2.80 m/s north. As the object moves north, we can consider this as a positive velocity.

The displacement during the 9.10 seconds can be calculated using the formula:

displacement = velocity * time

displacement = 2.80 m/s * 9.10 s
displacement = 25.48 m

Adding the initial position to the displacement, we get the final position:

final position = initial position + displacement
final position = -14.0 m + 25.48 m
final position = 11.48 m

Therefore, the final position of the object is 11.48 m north of the origin.