Question

A car starts has a position (in meters) given by x=kt^3 +2t where k is a constant ans t is in seconds. The velocity (in m/s) of the car at t=1 is:

Answer 1

If x = kx^3 + 2t,
V = dx/dt = 3kx^2 + 2

Plug in x = 1 and compute V.

I used calculus to get the velcoity equation.