Asked by Thomas
A car starts has a position (in meters) given by x=kt^3 +2t where k is a constant ans t is in seconds. The velocity (in m/s) of the car at t=1 is:
Answers
Answered by
drwls
If x = kx^3 + 2t,
V = dx/dt = 3kx^2 + 2
Plug in x = 1 and compute V.
I used calculus to get the velcoity equation.
V = dx/dt = 3kx^2 + 2
Plug in x = 1 and compute V.
I used calculus to get the velcoity equation.
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