Asked by Thomas

A car starts has a position (in meters) given by x=kt^3 +2t where k is a constant ans t is in seconds. The velocity (in m/s) of the car at t=1 is:

Answers

Answered by drwls
If x = kx^3 + 2t,
V = dx/dt = 3kx^2 + 2

Plug in x = 1 and compute V.

I used calculus to get the velcoity equation.
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