To solve this, we first need to find the total number of possible outcomes when selecting a number from the set {1, 2, 3, 4, 5, 6, 7, 8, 9}, which is 9.
a. Odd and divisible by 3:
The odd numbers in the set are {1, 3, 5, 7, 9} and the numbers divisible by 3 are {3, 6, 9}.
The numbers that satisfy both conditions are just 3 and 9, so the probability is 2/9.
b. Even or above 5:
The even numbers in the set are {2, 4, 6, 8} and the numbers above 5 are {6, 7, 8, 9}.
Combining both conditions, we have {2, 4, 6, 7, 8, 9}, and the probability is 6/9 or 2/3.
c. Not divisible by 4:
The numbers not divisible by 4 are {1, 2, 3, 5, 6, 7, 9}.
The probability is 7/9.
A number is chosen at random from (1, 2, 3, 4, 5, 6, 7, 8, 9). What is the probability that
it will be:
a. Odd and divisible by 3?
b. Even or above 5?
c. Not divisible by 4?
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