Asked by Queeneth
If a number is chosen at random from integers 5 to 25 inclusive, find the probability that the number is (a) multiple of 5 or 3 (b) even or prime number (c) less or greater than 18
Answers
Answered by
bobpursley
pr(multiple5) = pr(5)+pr(10)+pr(15)+pr(20)+pr(25)
= 5*pr(5)=5*1/21
pr even or prime=pr(even)+pr(prime)
= pr(6,8,10,12,14,16,18,20,22,24) + pr(5,7,11,13,17,19,23)
= 10/21+7/21=17/21
Pr(less or greater18)=1-pr(18)
= 1-1/21=20/21
= 5*pr(5)=5*1/21
pr even or prime=pr(even)+pr(prime)
= pr(6,8,10,12,14,16,18,20,22,24) + pr(5,7,11,13,17,19,23)
= 10/21+7/21=17/21
Pr(less or greater18)=1-pr(18)
= 1-1/21=20/21
Answered by
melody
queeneth, I dnt blieve u browse maths assynments....lol
Answered by
Davicjoe
Is it really correct
Answered by
Francis
Thanks was helpful🥰
Answered by
Fila
Amazing and kinda cool
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