A number consist of 3 digits.The middle digit is 0 and the sum of the first and last digits is 13.If the digits are reversed the number is increased by 297.Find the original number.MY SOLUTION: let x=the 1st digit & y=last digit x+y=13 i.e eqn1 & pls help

Answer 1

ok. you have

x+y = 13

The value of the number is 100x+y
So, reversed, it's 100y+x. So, your second equation is

100y+x = 100x+y + 297

Now just solve for x and y.

Answer 2

Great it is confusing some how