A novice skier starts from rest and slides down a frictionless 35 degree incline whose height is 125 m. How fast will she be going at the bottom?

3 answers

I'm not sure if this is right but my answer was 49.50 for the skier
Velocity 49.50
mgh=1/2 mv^2
v=sqrt(2gh)=sqrt(2*9.8*125)
that agrees with your answer