A novice skier, starting from rest, slides down a frictionless 31.0° incline whose vertical height is 123 m. How fast is she going when she reaches the bottom?

Answer 1

Her loss of GPE was mg*123
her gain of KE was 1/2 m v^2
set them equal, solve for v

Answer 2

V=sq.root(2gh)=sq.root(2 x 9.8 x 123m)=sq.root(2410.8)=49.09m/s