To find the acceleration of the rock, you can use Newton's second law of motion, which states:
\[ F = ma \]
where:
- \( F \) is the net force (in Newtons),
- \( m \) is the mass (in kilograms),
- \( a \) is the acceleration (in meters per second squared).
We can rearrange this equation to solve for acceleration (\( a \)):
\[ a = \frac{F}{m} \]
Given:
- \( F = 13 , \text{N} \)
- \( m = 1.3 , \text{kg} \)
Now plug in the values:
\[ a = \frac{13 , \text{N}}{1.3 , \text{kg}} = 10 , \text{m/s}^2 \]
Therefore, the acceleration of the rock will be \( 10 , \text{m/s}^2 \).
1 answer