A net force of 13 N is exerted on a rock. If the rock has a mass of 1.3 kg, what acceleration will it undergo?

1 answer

To find the acceleration of the rock, you can use Newton's second law of motion, which states:

\[ F = ma \]

where:

  • \( F \) is the net force (in Newtons),
  • \( m \) is the mass (in kilograms),
  • \( a \) is the acceleration (in meters per second squared).

We can rearrange this equation to solve for acceleration (\( a \)):

\[ a = \frac{F}{m} \]

Given:

  • \( F = 13 , \text{N} \)
  • \( m = 1.3 , \text{kg} \)

Now plug in the values:

\[ a = \frac{13 , \text{N}}{1.3 , \text{kg}} = 10 , \text{m/s}^2 \]

Therefore, the acceleration of the rock will be \( 10 , \text{m/s}^2 \).